Use mathematical modelling to solve applied problems involving growth and decay, including financial contexts; formulate problems, choosing to apply linear, quadratic or exponential models; evaluate and modify models and report assumptions, methods and findings.
Worked example
e.g.an amount of $24200 is invested. What interest rate grows it to $30356.48 in 2 years?
Write down list of informationP=24200,A=30356.48,n=2
Find a formula (memorise it)A=P(1+i)n
Substitute correct values into formula30356.48=24200(1+i)2
Remember i=times per year% as a decimal, and n=times per year×number of years
Solve for the asked value(1+i)2=1.2544∴1+i=1.12∴i=12%
Practice
Complete the following using the compound interest formula:
1
A=$3200,i=6.8%,n=7 years. Find P
AnswerP=$2019.07
2
P=$7500,A=$9447.84,n=3 years. Find i
Answeri=8%
3
P=$20500,i=12%,n=4 years. Find A
AnswerA=$32257.15
4
P=$5000,i=6%,n=10 years. Find A
AnswerA=$8954.24
5
P=$12000,i=4.5%,n=6 years. Find A
AnswerA=$15627.12
6
P=$800,A=$1000,i=4.7%. Find n (nearest year)
Answern=5 years
7
P=$30000,i=7%,n=3 years. Find A
AnswerA=$36751.29
8
P=$1000 at 10% compounded for 2 years. How much MORE than simple interest?
AnswerCompound $1210 vs simple $1200=$10 more
Next step
Practise Calculate Investment Interest with instant marking
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