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Year 7AC9M7N08

Dividing a Quantity in a Ratio

Recognise, represent and solve problems involving ratios.

Sharing in a ratio is a three-step routine: count the parts, find one part, then build each share. It never varies.

Builds onYr 7 · Ratios and Simplifying

Method

Add the parts to get the total
3:2  5 parts3:2 \ \Rightarrow\ 5 \text{ parts}
This tells you how many equal pieces to split the amount into.
One part is the amount divided by the total parts
Check by adding the shares back
They must total the original amount. This catches almost every error.

Worked example

e.g. Share $200 in the ratio 3:2\text{Share } \$200 \text{ in the ratio } 3:2
  1. Add the parts.3+2=5 parts3 + 2 = 5 \text{ parts}
  2. Divide the amount by the number of parts.200÷5=40(one part)200 \div 5 = 40 \quad \text{(one part)}
  3. Multiply for the first share.3×40=1203 \times 40 = 120
  4. Multiply for the second share.2×40=802 \times 40 = 80
  5. Check the shares add back to the total.120+80=200120 + 80 = 200 \quad\checkmark

Practice

Count the parts, find one part, then build each share.

1
Share 60 in 1:3\text{Share } 60 \text{ in } 1:3
Answer15 and 4515 \text{ and } 45
2
Share 350 in 4:3\text{Share } 350 \text{ in } 4:3
Answer200 and 150200 \text{ and } 150
3
Share 96 in 1:2:5\text{Share } 96 \text{ in } 1:2:5
Answer12, 24, 6012,\ 24,\ 60
4
Two people share in 5:3. The larger share is 250. Find the total.\text{Two people share in } 5:3. \text{ The larger share is } 250. \text{ Find the total.}
Answerone part =50400\text{one part } = 50 \quad\therefore\quad 400
5
Concrete is 1:2:4 cement, sand, stone. In 21 kg, how much sand?\text{Concrete is } 1:2:4 \text{ cement, sand, stone. In } 21 \text{ kg, how much sand?}
Answer6 kg6 \text{ kg}
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